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@Will.H
@rishavraj
AHHHH I don't remember how to do these >.< Lemme look it up real quick.
lol ok
is it? (Far arc - near arc)/2
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I can't even google it... I don't remember what this type of intersection is called XD LOL Inscribed angle? Subt... blahhh
@royalranger yes i think it should be
Yessss, 2 secant lines. Half of the difference between the arcs. Bahhh royal too smart for me >.<
ok but i still have no idea how to solve it .-.
So ya.. just do that then :) 1/2*(23-15)
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Subtract the arc lengths, then cut that in half.
oh ok hold on
1/2*(23-15) = 4?
Yayyy good job.
THANKS
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