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@baru
@welshfella
the value of the discriminant (b^2 - 4ac) can you do that?
the a b and c are the values in ax^2 + bx + c
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1?
compare 4x^2 + 9x + c with ax^2 + bx + 5 a = 4, b = ? and c = ?
b=9 and c=5
b^2 - 4ac = 9^2 - 4* 4*5 = 81-80 = 1 Yes 1 is correct. So what does that tell us about the roots?
AS its >0 it means that there are 2 roots and they are different and real numbers
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So C?
so we know its not A (not complex)
No as all the terms are positive the factors wil be of the form (hx + j)(hx + k) so the 2 roots will be negative.
Oh so negative?
we can factor it it comes to (x + 1)(4x + 5) = 0 so x = -1 ,-1.25
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yes 2 negative
OK?
So choice B =)
Thank you
B yes yw
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