Question

Solve the compound inequality. Show your steps.

3x + 2 ≤ 10 OR 3x + 2 ≥ 15

Answer 1

Subtract both sides by 2 Subtract both sides by 2
\(3x+2-2\le10-2\) or \(3x+2-2\ge15-2\)
\(3x\le8\) \(3x\ge13\)
Divide both sides by 3 Divide both sides by 3
\(\frac{3}{3}x\le\frac{8}{3}\) \(\frac{3}{3}\ge\frac{13}{3}\)

Answer 2

\(x\le?\) or \(x\ge?\)
solve it @JustSaiyan