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Need some help! For the function given, state the period: f(t)=6sin(3t-(pi/6))-1 (need help getting started, I'm pretty sure I remember what to do to solve.)
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that? \( f(t)=6 \sin(3t-(\pi/6))-1\)
\[f(t)=6\sin(3t-\frac{ \pi }{ 6 })-1\]
so yeah you have it right
and?
what exactly are you asking?
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DO YOU KNOW FORMULA sin(a-b)= ?
\[T = \dfrac{2 \pi }{3}\] that was obvious from the start, though? right?
I think this would help you.
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