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Mathematics 12 Online
OpenStudy (uscrnamc):

please help question below

OpenStudy (uscrnamc):

jhonyy9 (jhonyy9):

so than you check this graph you see that for g(0) you need getting 2 but in case of f(x) = 4^x for x=0 will get f(0) = 4^0 = 1 so how you think what is the function of g(x) = ?

jhonyy9 (jhonyy9):

do you understand me please ? than you see g(0) need being equal from the graph 2 and you know that f(0) =4^0 = 1 so g(0) = f(0) + how many ? for you get from 1 this necessary 2

OpenStudy (uscrnamc):

sorry no im not getting what you are saying

jhonyy9 (jhonyy9):

you know that f(x) = 4^x and there is this graph of g(x) what is a transformation on f(x) so with these knowladges you need getting g(x) = ? yes ?

jhonyy9 (jhonyy9):

how you get from f(x) the g(x) with this graph ?

OpenStudy (uscrnamc):

idk if the line = g(x) then the points makes up the answer right

jhonyy9 (jhonyy9):

believe it please this is the right way but you can prove it for f(1) = 4^1 = 4 and than you check this graph g(1) = 5

OpenStudy (uscrnamc):

would it help if i had the actual f(x) graphed next to the graph of g(x) i was given

jhonyy9 (jhonyy9):

no this is the way how you get from f(x) this g(x) f(0) = 1 so g(0) = f(0) + ? when you know that g(0) need being equal 2

jhonyy9 (jhonyy9):

g(0) = f(0) +x 2 = 1 + x x = ?

OpenStudy (uscrnamc):

0?

jhonyy9 (jhonyy9):

no 2=1+x subtract from both sides 1 what will get ?

jhonyy9 (jhonyy9):

2-1 = 1-1+x ? = X

OpenStudy (uscrnamc):

1?

jhonyy9 (jhonyy9):

yes sure this is easy - courage please bc. than you add to f(x) this one f(0) = 1 so g(0) = f(0) +1 = 1+1 = 2 ok. now ? do you understand it ?

jhonyy9 (jhonyy9):

just for you believe it than you check this graph for g(1) you need getting 5 so than g(x) = f(x) +1 so than you get for x=1 f(1) = 4^1 = 4 so g(1) = 4^1 +1 = 4+1 = 5 ok. ? do you believ it now ?

OpenStudy (uscrnamc):

sure

jhonyy9 (jhonyy9):

yes sure hope helped was my pleasure good luck bye bye

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