Question

Determine the number and type of complex solutions and possible real solutions for each of the following equations.

1) 2x2 + 5x + 3 = 0 x=-1,-3/2

2) 4x3 – 12x + 9 = 0

3) 2x4 + x2 – x + 6 = 0

Answer 1

@zepdrix

Answer 2

hint: use Descartes rule of signs, do the f(x) and f(-x) signs check

Answer 3

With deference to jdoe0001, I'd suggest that you just find the discriminant of the given quadratic.

What are the coefficients a, b and c of this quadratic?

Form and evaluate the discriminant\[b^2-4ac\]

Answer 4

If the discriminant is + there will be 2 real, unequal roots.
If 0 there will be 2 real, equal roots.
if the discrim. is -, there will be 2 complex roots