I will fan n medal :P
The measurement of the width of a garden plot is 44 m. Its actual width is 45.5 m.

What is the percent error in the measurement, to the nearest tenth of a percent?

Question

I will fan n medal :P 
The measurement of the width of a garden plot is 44 m. Its actual width is 45.5 m.

What is the percent error in the measurement, to the nearest tenth of a percent?

chiunlee12 · Answer

The formula for percent error:
(Measured - accepted value)/accepted value

chiunlee12 · Answer

(44-45.5)/45.5

alayrhi · Answer

That would be -0.032967032967033 ?

chiunlee12 · Answer

Solve for that and it will give you the final answer. Not to mention this equation gives an ABSOLUTE value, meaning that the percentage will always be positive

chiunlee12 · Answer

It should be correct, but remember it asks for the percentage, so you multiply your small decimal by 100

alayrhi · Answer

Ohh okay. Thanks ^_^

chiunlee12 · Answer

Yeah no problem