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f(x)=2x2+3 for f(-3) I tried and I got -9 but it was marked wrong and I tried again and got the same answer.
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Is that your function? \[\Huge f(x)=2\color{red}x^2+3\]
f(x) = 2x2 + 3
I don't think so
to find f(-3) replace the x in 2x^2 + 3 with -3 and simplify f(-3) = 2*(-3)^2 + 3
It isn't displayed as an exponent
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have you got a picture of the original question?
I copied and pasted this: 8. Given f(x) = 2x2 + 3 find f(-3).
the answer would be -9 if the function was 2*x*2 + 3
Okay I will contact my teacher thank you for your help.
but since the answer is not -9 we must take the second '2' to be an exponent
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