Question

remainder theorem - p(-4): P(x)=x^3+3x-8 ???

Answer 1

hmmm

Answer 2

?

Answer 3

\(\bf p(-4)\iff x=-1\implies (x+4)=0
\\ \quad \\
p(x)=x^3+3x-8 \iff p(x)=1x^3{\color{brown}{ +0x^2}}+3x^1-8\qquad thus
\\ \quad \\

\begin{array}{llllll}
-4&|&1&0&3&-8\\
&|&\square ?
\\\hline\\
&&1
\end{array}\)


in your synthetic division, to get the remainder, and thus use it in p(x) I assume
you missed the next exponent of "x", 2, from 3 to 1, should be 3, 2,1 anyhow
and you also used 8 for the constant, but looking closer, is -8

Answer 4

thank you