Question

for a segment AB

AB^2 = Δx^2 + Δy^2
so
AB = squareroot(Δx + Δy)

Δx(Delta x) is always the difference in two values x1 and x2

so in this case

Δx = xA - xB
and
Δy = yA - yB

Answer 1

Evil this was supposed to be a reply