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A quartic function contains x^4 so it will have 4 zeroes. D is linear so it cant be D B is the graph of x^3 so Not B C is definitely possible
- it would have 4 complex zeroes so they wouldnt appear on the graPh and the x^4 would produce a U shape
Not sure about A Could there be more than one correct option?
Yea there could be 3 0 roots and one non zero A is also a possibility so A and C
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>
?
the graph of f(x) = x^3(x + 2) would look like A
theres 2 possibilities A and C
OK Im sure of this one,
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I've drawn the graphs on desmos to check it out
both A and C
U need one answer though
well go for C
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