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differentiating a fourier series
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this is the fourier series for x^2 http://imgur.com/a/ZzewB I am asked to find a fourier series for x by differentiating the above fourier series. My attempt is to differentiate and then divide by 2 but my answer does not match the answer key
my work:\[x = \frac{ 1}{ 2 }\frac{ 4 }{ n^2 } n (-1)^{n-1} * n(-\sin(nx))\]
\[x = 2(-1)^{n-1}*(-\sin(nx))\]
\[x = \frac{ 2(-1)^{n} }{ -1 } * (-\sin(nx))\]
\[x = 2(-1)^{n}\sin(nx) = my answer\]
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however the answer key is \[x = 2(-1)^{n+1}\frac{\sin(nx)}{n}\]
(just pretend there are sigma signs in front of each answer, I forgot to draw them)
oh wait I figured it out
hm...
\((-1)^n = (-1)^{n+1}\cdot \frac{1}{n}\) :)
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