4 goes in to 19 4 times with a remainder of 3, so \(i^{19}=i^3=-i\)
satellite73:
i can't read 12
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zarkam21:
Hey
zarkam21:
I'm back
zarkam21:
@satellite73
zarkam21:
10 is i^19
11 is I^97
zarkam21:
@satellite73
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zarkam21:
@Nnesha
Nnesha:
|dw:1489086876838:dw|
4 steps and then after i^4 it repeats the same pattern again
i=i^5
i^2=i^6
to find the value of i to the larger number you just have to find the remainder of \[\large\rm \frac{ whatever~power }{ 4 } = i^{remainder}\]
Nnesha:
\\[i^2=\sqrt{-1} \cdot \sqrt{-1} = -1\]\[i^3=\color{red}{i^2} \cdot i = \color{Red}{(-1)} i =-i\]\[i^4 = i^2 \cdot i^2 = (-1)(-1)=1\]
Nnesha:
\
zarkam21:
Okay so 10 would be?
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Nnesha:
hmm latex doesn't work for i =i= sqrt{-1} **
Nnesha:
divide 10 by 4 (
how many times doe 4 go into 10 what will be the remainder ?
zarkam21:
2.5
Nnesha:
4 times 1=4
4 times 2=8
4 times 3=12 (12 is bigger than 10) so we don't add this)
4 times 2=8 (4 goes into 10 2 times )
and the remainder will be 10-8=2
therefore we got i^2 which is ?
zarkam21:
what you wrote above right?
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zarkam21:
like what you wrote for I^2
zarkam21:
can we please hurry I have 10 mins
Nnesha:
any doubt ?
zarkam21:
NO doubt but is that the answer for 10?
Nnesha:
to find i^10
divide 10/4
and then set i^(remainder) and then simplify
remainder is 2 so i^2
now simplify
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zarkam21:
so I ^19 would be
zarkam21:
no no we have to find I^19
Nnesha:
okay... do the same thing..
zarkam21:
So um divide right
Nnesha:
yes
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zarkam21:
19 by 4?
Nnesha:
yes right
because its a 4 steps cycle i've posted above
zarkam21:
I got 4.75
Nnesha:
oky so what is the remainder
zarkam21:
.75?
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Nnesha:
no calculator will not give you the remainder
19/4= 4.75 the number before decimal represent how many times 4 goes into 19
what's what is 4 times 4 = ??
subtract that from the power(19) that will be the remainder
zarkam21:
4*4 is 16
zarkam21:
19-16=3
Nnesha:
yes right so what will be the answer ?
zarkam21:
I^3
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Nnesha:
yes right what i^3 equal to what ?
zarkam21:
what you have written above right?
Nnesha:
yes
zarkam21:
Is that the final answer then
Nnesha:
yes
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zarkam21:
okay what about I^97
Nnesha:
same thing
zarkam21:
Okay so 97/4
Nnesha:
yes
zarkam21:
which is 24.25
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zarkam21:
so 97-16?
Nnesha:
what is 16 ??
zarkam21:
isn't it 4*4
Nnesha:
[24].25
all the numbers before decimal
zarkam21:
ohh so 97-24?
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Nnesha:
hmm no multiply that by 4
zarkam21:
96
zarkam21:
so I^1
Nnesha:
yes.
zarkam21:
is it the power of -1?
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Nnesha:
i^1 is same as i
zarkam21:
so that would be?
Nnesha:
|dw:1489089100439:dw|
zarkam21:
I just need help with 2 more questions if you don't mind :/
Nnesha:
depends on the question is it same as this >
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Nnesha:
|dw:1489089520879:dw|
now add the number in the column
zarkam21:
-16
Nnesha:
hmm wait 1 is not negative
zarkam21:
-14?
Nnesha:
|dw:1489089593807:dw|
now repeat the same steps
multiply -14 by -3 and write that above the line in 3rd column
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zarkam21:
42
Nnesha:
yep
zarkam21:
is that the x ?
Nnesha:
|dw:1489089684112:dw|
Nnesha:
yes
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zarkam21:
Okay next problem =)
zarkam21:
SO number 15 is x=42 right?
Nnesha:
yes
zarkam21:
OKay next problem
Nnesha:
its the same thing just backwards
remember we multiplied *some numbers * with first number in order to find the number for second column |dw:1489089823547:dw|
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Nnesha:
*some number ***
zarkam21:
So 20?
Nnesha:
|dw:1489089995843:dw|
that's how for the first question there is -3 |dw:1489090038390:dw|
Nnesha:
what's 20 ?
zarkam21:
Oh -3?
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Nnesha:
yes but remember that's an example
like for #15 how would we find |dw:1489090202991:dw|
this number if it wasn't given
Nnesha:
now do the same thing for #16
zarkam21:
4/2
Nnesha:
yes.
zarkam21:
So x would equal 2?
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Nnesha:
yes
zarkam21:
Thank you so much that is all
Nnesha:
yw
Allison:
If this question has been answered, please close it. Thank you! :)