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Factor x2 - 16 = 0. (x + 4)(x - 4) = 0 (x + 4)(x + 4) = 0 (x - 2)(x - 8) = 0 (x + 2)(x - 8) = 0
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Apply difference of squares: \(\sf (a^2-b^2)= (a+b)(a-b)\)
can you explain to me everything?
To factor this problem, you have determine what squares will equal \(\sf x^2\) and 16. For example, you have \(\sf x^2-4\) x squared will give \(\sf x^2\), so x will be your a (obviously) and \(\sf 2^2\) will give you 4, so 2 will be your b so the answer for this one will be \(\sf (x-2)(x+2)\) Now, apply the same method for your question
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