Ask your own question, for FREE!
Mathematics 7 Online
rootbeer003:

(y+5)+(3y-9) sum?

rootbeer003:

@Hero

Hero:

Where did you get this question from? Is it posted somewhere? May I see the original page from which it is posted? Can you upload it as a picture?

rootbeer003:

I cant and im kindof in a hurry

Hero:

Hint: (y + 5) + (3y - 9) = (3y + y) + (5 - 9)

rootbeer003:

4y-4?

Hero:

Correct

rootbeer003:

(m-4)(m+3) Find the product

rootbeer003:

m^2-m-12?

Hero:

Basically, for this you have to apply the distributive property for the first couple steps: (m - 4)(m + 3) = m(m + 3) - 4(m + 3) = m^2 + 3m - 4m - 12 = m^2 - m - 12 Correct

rootbeer003:

(m-7)(9m-1)

Hero:

Same logic applies

rootbeer003:

(9+4s)(4+s) i rly need help on this one

Hero:

What happened to (m-7)(9m-1)?

rootbeer003:

i got 9m^2-64m+7

rootbeer003:

Correct?

Hero:

Correct, but how did you get that? Can you show me the work you did?

rootbeer003:

Im kinda in a hurry il show u after

Hero:

How many questions do you have remaining?

rootbeer003:

i still have 1 that i have no idea to solve

rootbeer003:

(9+4s)(4+s)

Hero:

The same logic applies. How'd you manage to solve the others? Maybe this will help: (9 + 4s)(4 + s) = (4s + 9)(s + 4)

rootbeer003:

Ehhh so what would the product be?

Hero:

Are you not able to find the product of (4s + 9)(s + 4) ?

rootbeer003:

no

Hero:

How'd you manage to find the products of the previous two problems? The steps are similar to this one.

rootbeer003:

cause im confused

rootbeer003:

Can u please just help me, its my last one

Hero:

Show me exactly where you get confused.

rootbeer003:

ok i gtg thanks for ur help

Hero:

K bye. You're welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!