Question

a ball is released from rest at a certain height. its velocitt after falling 256ft is

Answer 1

use kinematic equation to find t first \[ \Delta y = v_i t+\frac{1}{2}at^2\]
where v_i is the initial velocity
since the ball is released from rest vi=0

Answer 2

falling 256ft =y
\[\large\rm 256 = (0)t +\frac{1}{2}g t^2\] solve for t

Answer 3

g=32 ft/s

Answer 4

once u get the time you can use the following kinematic equation to find final velocity \[\huge\rm v_f=v_i +g t\]

Answer 5

@rocorici