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talab:

A Wheatstone bridge ABCD (labelled in clockwise direction) with a galvanometer G joined to the junctions B and D. A cell E is connected across AC. Resistances of 15, 10, 4 and X ohms are inserted into the arms AB, BC, CD and DA respectively. The value of X is ----- ohms

sillybilly123:

Question incomplete. **IFF** G is reading 0, then \(\dfrac{X}{4} = \dfrac{15}{10}\) ... and solve

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