Question

Given the function f(x) = log2(x + 6), find the value of f−1(3).
f−1(3) = 2
f−1(3) = 3
f−1(3) = 9
f−1(3) = 18

Answer 1

The first one :O

Answer 2

I don't have paper with me so I need to work this out here

Answer 3

Okie Dokie

Answer 4

y = log2(x+6)

x = log2(y+6)

2^x = 2log2(y+6)

2^x = y + 6

y = 2^x - 6

Answer 5

yeah I get A as well

Answer 6

Okie thank you! I will be right back