Question

Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 3.

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y ≈ 4.01
y ≈ .79
y ≈ 1.58
y ≈ 0.47

Answer 1

@Vocaloid

Answer 2

is your equation typed correctly?

Answer 3

Let me check o.o

Answer 4

is it 2^(2y) = 3?

Answer 5

Yes ^_^, sorry I forgot to use the "^" Symbol e.e

Answer 6

log_2(3) = 1.6 ish
so if 2y = 1.6 then g is about 0.79 so B?

Answer 7

Yes! That's what I have :D

Answer 8

Jesus I bet it took you 5 seconds ._.

Answer 9

To get through log "