Question

What is the sum of a 58-term arithmetic sequence where the first term is 6 and the last term is 405?
11,097
11,508
11,919
12,330

Answer 1

sum = n*(a1 + an)/2

n = number of terms
a1 = first term
an = last term

Answer 2

58(6 + 405)/2

Answer 3

Yes and that equals...?

Answer 4

11919

Answer 5

Awesome

So that's you r answer