Question

hat are the steps for using a compass and straightedge to construct a square?

Drag the steps and drop them in order from start to finish.
Construct horizontal ​ HJ¯¯¯¯¯ ​
Construct a circle with point M as the center with radius MJ .
Construct a circle with point H as the center and a circle with point J as a center with each circle having radius HJ .
Label the point of intersection of the two circles above​ ​ HJ¯¯¯¯¯ ​​, point K, and the point of intersection of the two circles below ​ HJ¯¯¯¯¯ ​, point L.
Construct KL¯¯¯¯¯ , the perpendicular bisector of ​ HJ¯¯¯¯¯ ​, intersecting​ ​ HJ¯¯¯¯¯ ​ ​​at point M.
Construct HN¯¯¯¯¯¯ , NJ¯¯¯¯¯ , JO¯¯¯¯¯ , and OH¯¯¯¯¯¯ to complete square HNJO .
Label the point of intersection of circle M and ​ KL¯¯¯¯¯ ​ closest to point K, point N, and the point of intersection of circle M and ​ KL¯¯¯¯¯ ​ closest to point L, point O.

Answer 1

@Vocaloid

Answer 2

Thank yew! ^~^

Answer 3

Here is my attempt at ordering the steps:

Answer 4

Construct horizontal ​ HJ¯¯¯¯¯ ​

Answer 5

Construct a circle with point M as the center with radius MJ .

Answer 6

Construct a circle with point H as the center and a circle with point J as a center with each circle having radius HJ .

Answer 7

Label the point of intersection of the two circles above​ ​ HJ¯¯¯¯¯ ​​, point K, and the point of intersection of the two circles below ​ HJ¯¯¯¯¯ ​, point L.

Answer 8

Construct KL¯¯¯¯¯ , the perpendicular bisector of ​ HJ¯¯¯¯¯ ​, intersecting​ ​ HJ¯¯¯¯¯ ​ ​​at point M.

Answer 9

Label the point of intersection of circle M and ​ KL¯¯¯¯¯ ​ closest to point K, point N, and the point of intersection of circle M and ​ KL¯¯¯¯¯ ​ closest to point L, point O.

Answer 10

Construct HN¯¯¯¯¯¯ , NJ¯¯¯¯¯ , JO¯¯¯¯¯ , and OH¯¯¯¯¯¯ to complete square HNJO .

Answer 11

sorry for the delay, this is my first time trying a problem like this so I had to look some stuff up

Answer 12

It's OK, thank you for the help