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Mathematics 17 Online
SkinnyMinnie20:

Find the values of x and y in parallelogram PQRS at the right. What are PR and SQ?

ThisGirlPretty:

@Vocaloid

SkinnyMinnie20:

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Vocaloid:

the diagonals bisect each other so y = x + 1 2x = 3y - 7

Vocaloid:

we can do a substitution to get 2x = 3x + 3 - 7 x = ?

Vocaloid:

@SkinnyMinnie20 still there?

SkinnyMinnie20:

yes im here

SkinnyMinnie20:

x=4

Vocaloid:

good now we let x = 4 to find y (y ends up being 5 using the first equation)

Vocaloid:

then you just calculate PR and QS using the diagram

Vocaloid:

PR = 3y - 7 + 2x QS = y + x + 1

SkinnyMinnie20:

okay so y=5

Vocaloid:

still there?

SkinnyMinnie20:

yes I said it would be y=5

Vocaloid:

ok but what did you get for PR and QS?

SkinnyMinnie20:

PR=4 QS=5

Vocaloid:

no

Vocaloid:

x = 4 and y = 5

Vocaloid:

PR = 3y - 7 + 2x QS = y + x + 1

Vocaloid:

^ calculate PR and QS.

SkinnyMinnie20:

How?

Vocaloid:

you are given x and y. you are given the formulas for PR and QS in terms of x and y.

Vocaloid:

again... PR = 3y - 7 + 2x QS = y + x + 1

SkinnyMinnie20:

so replace x and y with 4 and 5

Vocaloid:

yes

SkinnyMinnie20:

okay

SkinnyMinnie20:

PR=16 QS=10

Vocaloid:

good that's your answer

SkinnyMinnie20:

Okay thank you very much

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