Mathematics
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SkinnyMinnie20:
Find the values of x and y in parallelogram PQRS at the right. What are PR and SQ?
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ThisGirlPretty:
@Vocaloid
SkinnyMinnie20:
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Vocaloid:
the diagonals bisect each other so
y = x + 1
2x = 3y - 7
Vocaloid:
we can do a substitution to get
2x = 3x + 3 - 7
x = ?
Vocaloid:
@SkinnyMinnie20 still there?
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SkinnyMinnie20:
yes im here
SkinnyMinnie20:
x=4
Vocaloid:
good
now we let x = 4 to find y (y ends up being 5 using the first equation)
Vocaloid:
then you just calculate PR and QS using the diagram
Vocaloid:
PR = 3y - 7 + 2x
QS = y + x + 1
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SkinnyMinnie20:
okay so y=5
Vocaloid:
still there?
SkinnyMinnie20:
yes I said it would be y=5
Vocaloid:
ok but what did you get for PR and QS?
SkinnyMinnie20:
PR=4
QS=5
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Vocaloid:
no
Vocaloid:
x = 4 and y = 5
Vocaloid:
PR = 3y - 7 + 2x
QS = y + x + 1
Vocaloid:
^ calculate PR and QS.
SkinnyMinnie20:
How?
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Vocaloid:
you are given x and y.
you are given the formulas for PR and QS in terms of x and y.
Vocaloid:
again...
PR = 3y - 7 + 2x
QS = y + x + 1
SkinnyMinnie20:
so replace x and y with 4 and 5
Vocaloid:
yes
SkinnyMinnie20:
okay
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SkinnyMinnie20:
PR=16
QS=10
Vocaloid:
good that's your answer
SkinnyMinnie20:
Okay thank you very much