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the height of a golf ball hit in the air is modeled by the equation h(t)+-16t^2+48t, where h represents the height, in feet, and t represents the number of seconds that have passed since the ball was hit. What is the height of the ball after 2 seconds.
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let t = 2 and calculate h(2)
-64
-16t^2+48t = -16(2^2) + 48(2) = ?
t = 2,1
-16(2^2) + 48(2) = ?
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ohhh sorry i meant 32
good 32 is your answer
thx
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