Question

Ben uses a compass and a straightedge to construct ∠DEF ≅ ∠ABC, as shown below:

The art shows two figures. The figure on the left shows two rays BA and BC having a common end point B. An arc drawn from B cuts the ray BA at H and the ray BC at I. The figure on the right shows two rays ED and EF having a common end point E. An arc drawn from E cuts the ray ED at J and the ray EF at K. Another arc drawn from K cuts the ray ED at J.

Which statement best explains why Ben uses the width BI to create the arc JK from point E?

∠DEF ≅ ∠ABC when BH = EK, BI = JK, and HI = EJ.
BI = JK when ∠DEF ≅ ∠ABC
BI = EJ when ∠DEF ≅ ∠ABC
∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK.

Answer 1

@Vocaloid @Angle

Answer 2

@Bearclaws72 Do you have a guess?

Answer 3

I got it right dont worry