Help please
@Shadow @Vocaloid
this might be wrong but 30 and 28
@Vocaloid
okay so lets start with question 1 :)
total students are 10 and there are 3 positions for winners. so we have |dw:1507130265703:dw|
now question arises what is the condition of winning gold out of 10 students
the answer is we have 10 ways to winning gold because out of 10 students ,all likely have same winning chances to win gold
now, suppose someone won gold,so there are 9 ways to win silver because there are 9 students left and all have same equal chances
similarly for bronze ,we have 8 ways
so finally|dw:1507130483812:dw| to find no of ways ,just multiply them so \(\large \bf 10 \times 9 \times 8=720\) That's our answer :)
if you get online ,we'll solve question 2
Iam here
@loveboy
@Vocaloid
Use the combination formula n!/(r!(n-r)!)
n = total number and r = group size
Reread the problem please
We are talking about the books
Good that's it
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