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1. f(x) = x^2 -6x + 9 Factor (x - 3)(x - 3) Zeros, x - 3 = 0 x = 3 So, the graph of the function touches the x-axis at x = 3
2
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For Number 2, it is the second option. This is because in f(x) = 2x^5 - x^4 -2x^3 + 4x^2 + x - 2 there are three changes in signs (positive and negative) with this being the positive case (as per f(x) ). Therefore we know that there are three or one positive zeroes.
number 3
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Second, doing some testing.
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When you input x for 0 and 2 you get 5 and -17. In between those two is zero, therefore those points are your answer.
so c
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