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1. f(x) = x^2 -6x + 9 Factor (x - 3)(x - 3) Zeros, x - 3 = 0 x = 3 So, the graph of the function touches the x-axis at x = 3
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For Number 2, it is the second option. This is because in f(x) = 2x^5 - x^4 -2x^3 + 4x^2 + x - 2 there are three changes in signs (positive and negative) with this being the positive case (as per f(x) ). Therefore we know that there are three or one positive zeroes.
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Second, doing some testing.
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When you input x for 0 and 2 you get 5 and -17. In between those two is zero, therefore those points are your answer.
so c
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