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Help please
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you would let B(t) = 1000 and solve for t
I don't know what mathway's on about, I solved it just fine
start by dividing both sides by 1000
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that gives us 1=50*e^0..5t right
make sure to apply the division to both sides
50*e^0.5t divided by 1000 = ?
\[\frac{ e ^{0.5t} }{ 20 }\]
good now try solving for t
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right now you have 1 = e^(0.5t)/20 solve for t
okay t=5.99146
good, now we round that to the nearest integer which is...?
6
good so your answer is 6
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666 >:)
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