Question

https://s1.postimg.org/29ne7fetpr/Capture.png

Answer 1

@sillybilly123

Answer 2

i have 4 more after this but this one is just to check answers

Answer 3

the one on the left is the only 1 that can be global, right?!?!

Answer 4

yes

Answer 5

and the 2 in c) are local?

Answer 6

i would guess so

Answer 7

is it b and c

Answer 8

@Vocaloid hate to bother you but something doesn't seem right

Answer 9

the other question you answered you do realize it's to the 9th root right

Answer 10

kay. slow down !!

Answer 11

There is no globalmaximum so b is not right

Answer 12

it's c and d

Answer 13

\(\checkmark\)

Answer 14

Right

Answer 15

https://s1.postimg.org/3l6mw9a15b/Capture.png
is this a?

Answer 16

yes, it's an odd function

Answer 17

after this only 4 more questions and then i promise you won't have to hear from me until next week at least in this subject

Answer 18

yeah when i saw to the 9th power i kinda don't think it's a

Answer 19

Actually nvm it's a

Answer 20

it is ok

Answer 21

The highest power has to be odd and the leading coefficient must be positive

Answer 22

https://s1.postimg.org/47ikp28sf3/Capture.png

Answer 23

So yeah silly was right

Answer 24

ok ths questin im lost

Answer 25

I'm not sure how to approach this 1

Answer 26

Silly I'll leave it to you

Answer 27

@sillybilly123

Answer 28

the other solutions will be the conjugates

Answer 29

right?

Answer 30

so the opposites

Answer 31

b?

Answer 32

https://s1.postimg.org/800t6zlw27/Capture.png

Answer 33

for a complex number \(z = a + i b\), it's conjugate, \(z^*\), is \( z^* = a - i b\)

Answer 34

so \(z \cdot z^{*} = a^2 + b^2 = |z|\)

Answer 35

wait which question are we talking about

Answer 36

is b the answer for that one question?

Answer 37

@Vocaloid