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@Vocaloid
@Nnesha
Mid point is \(\bf (\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})\) Plug in what you have \(\bf (\dfrac{0+2a}{2},\dfrac{2b+0}{2})\) You need the y value which is (2b + 0)/2 2b + 0 = 2b 2b/2 = b So it will be (a, b)
That's for the first answer (b)
thank you ! do you know the others?
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