Question

In one type of dog, black spots (B) are dominant over brown spots (b) and long tails (L) are dominant over short tails (l). Complete a dihybrid cross for parents with the genotypes: BbLL × BBLl and answer the following in complete sentences.

Describe how you would set up a Punnett square for this cross.
List the likelihood of each possible offspring genotype.
List the likelihood of each possible offspring phenotype.

Answer 1

@JustSaiyan

Answer 2

@JustSaiyan

Answer 3

draw a 4x4 square
and write down the possibilities of what they could produce

Answer 4

I honestly dont have time but I will try

Answer 5

Im just starting this lesson so not really sure about punett squares

Answer 6

`BbLL `
4 possibilities
\[ \huge\rm \color{red}{B}\color{blue}{b}\color{green}{L}\color{orange}{L}\]
\[ \large \rm \color{red}{B}\color{green}{L} , \color{red}{B}\color{orange}{L}, \color{blue}{b}\color{green}{L},\color{blue}{b}\color{orange}{L}\]

Answer 7

Ok

Answer 8

you don't have time for this question ?

Answer 9

Yes I do sorry

Answer 10

oh good.

Answer 11

Just limited because I'm on safari on my iphone XD

Answer 12

So cant do images and all that

Answer 13

so what will be the possibility from this genotype `BBLl `

Answer 14

I dont understand what a genotype is I just did the Dba

Answer 15

Sorry in advance for my stupidity

Answer 16

i don't know what dba is.
the geneotypes are given in the question BBLl
so what are the possibilities to produce black spot/long tails ?

capital letter represent the dominant alleles
and the small letter represent the recessive alleles

Answer 17

for dihybrid cross you have to draw a box like this
4 by four

Answer 18

Ok

Answer 19

A Dba is a Discussion based assesment I call my teacher and then I get to move on

Answer 20

given two geneotypes from parents
lets say BBLl from male (black spots and long tails are dominant)
and BbLL from female (black spots and long tails are dominant)
we can the male Genotype at the top and female Genotype vertical

Answer 21

we can write the **

Answer 22

now we just gonna multiply one possibility from left with all the possibilities at the top makes sense ?

Answer 23

Ok

Answer 24

Im slowly understanding

Answer 25

ok cool now try to fill the 2nd row
multiply the 2nd pair on the left side with all the pairs at the top

Answer 26

Ok wait how do I multiply them?

Answer 27

Oh wait I think I know

Answer 28

Is it (Left to right)
1. BbLl
2.Bbll
3.bBLl
4.BBLI

Answer 29

?

Answer 30

^ that should be in the first box 2nd row

Answer 31

So its the same thing twice?

Answer 32

yes correct

Answer 33

now try to fill the 3rd row

Answer 34

1.BBLl
2.BbLL
3.BbLl
4.bbLL
???

Answer 35

hmm first one is correct
here is how u should multiply

Answer 36

last row will be the same

Answer 37

Ok

Answer 38

So thats how to setup the punnett square right?

Answer 39

yes

Answer 40

Ok

Answer 41

now you have to find possilbe genotype and phenotype

Answer 42

Just what I was about to ask XD

Answer 43

Ok
So how do we do it

Answer 44

how do you wanna write it as a percent or ratio ?

Answer 45

Uh Percent

Answer 46

That would probaly give us a more accurate answer right?

Answer 47

the answer will still be accurate if we write it as ratio

Answer 48

Ok but lets still right it as a percentage X'D

Answer 49

BBLl:25% Black Spot Long Tail: 100%
BBLL: 25% Black Spot Short Tail: 0%
BbLl: 25% Brown Spot Long Tail: 0%
BbLL: 25% Brown Spot Short Tail: 0%
BBll: 0%
bbLL: 0%
bbLl: 0%
bbll: 0%

Answer 50

okay
Genotype:
we have 16 boxes so out of 16 how many boxes contains the pair BBLL ?

Answer 51

Four

Answer 52

\[\frac{4}{16} \times 100 =25% \]
so 25% of BBLL

Answer 53

25%

Answer 54

4/16 times 100 = 25% of BbLL

Answer 55

Ok

Answer 56

cross out the box that u already counted
4/16 times 100 = 25% of BBLl

Answer 57

left with last four box BbLl
which is also 25%

Answer 58

Ok so thats the percentages 25% and 25%?

Answer 59

so
BbLl
BBLl
BbLL
BBLL
all are 25%

Answer 60

So thats the answer ALL ARE 25% ACCEPT IT

Answer 61

phenotype represents the dominant alleles
so like i said earlier even if there is one capital letter that will represent the dominant over other color/shape

Answer 62

Bb =capital B so black color is dominant over brown
BB= both are capital so definitely black color dominant over brown
LL= long tails are dominant over short tails

Answer 63

so if you look at this table none of them have the pair bb or ll so what will be the percent for dominant alleles ?

Answer 64

0%

Answer 65

???

Answer 66

plzexplain why u came up with that answer

Answer 67

so if you look at this table none of them have the pair bb or ll so what will be the percent for dominant alleles ?

Answer 68

^
What you said non of them have a pair

Answer 69

dominant alleles are represented by the capital letter.

Answer 70

yes right i said the pair `bb` or ` ll`

Answer 71

even if only one letter of the pair is capital, it will be dominant
BB (both are capital letters so black spots are dominant )
Bb(one is capital B so the black spot is still dominant over brown )

Answer 72

ok

Answer 73

so is there any box that contains recessive alleles ( small letter pairs, such as bb , ll)

Answer 74

Yes

Answer 75

should I name them?

Answer 76

ok draw a circle around them

Answer 77

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nnesha
even if only one letter of the pair is capital, it will be dominant
BB (both are capital letters so black spots are dominant )
Bb(one is capital B so the black spot is still dominant over brown )
\(\color{#0cbb34}{\text{End of Quote}}\)
`even if only one letter of the pair is capital, it will be dominant `
so Bb is still dominant over brown color

Answer 78

Ok

Answer 79

there is no box with the bbll or bbLL or BBll

Answer 80

so all of them are dominant
phenotype will be 100% blackspots and long tails

Answer 81

Oh ok so thats it?

Answer 82

25% and 100%

Answer 83

yes

Answer 84

but don't forget to write the alleles

Answer 85

you can't just say genotype is 25%
you have to mention each allele
BBLL=25% & so n