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Mathematics 18 Online
PandaSurvive:

Halp meh please *-*

PandaSurvive:

1 attachment
Vocaloid:

|dw:1509400688661:dw|

Vocaloid:

|dw:1509400697687:dw|

Vocaloid:

A = (1/2) * (b1+b2) * h you will have to use the distance formula to find b1, b2, and h

PandaSurvive:

ah oki

PandaSurvive:

to find b1 and b2 the formula is ab= square root of (x2-x1)^2 + (yz-yz)^2 ?

PandaSurvive:

*y2 and y1

Vocaloid:

yes

PandaSurvive:

for a to b i got 5

Vocaloid:

good, that's your h value, now find b1 and b2 using the same method

PandaSurvive:

for a to d i got 13.416

Vocaloid:

check your math again, it should be a whole number

Vocaloid:

you might have missed a sign somewhere

PandaSurvive:

i keep getting the same answer, (-13-(-1))^2+(-11-5)^2 then -12^2 and -6^2

PandaSurvive:

getting 144 and 36

Vocaloid:

-11-5 is not -6

PandaSurvive:

oh god im stupid

PandaSurvive:

x'D

PandaSurvive:

ok its 20 for AD

Vocaloid:

good, now all that's left is BC

PandaSurvive:

its 5

Vocaloid:

awesome, so then we just plug that in to (1/2)(b1+b2)*h = (1/2)(5+20)*5 = ?

PandaSurvive:

62.5

Vocaloid:

good, that's what I got as the answer too

PandaSurvive:

thank you cx

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