Mathematics
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zarkam21:
-2x+6y???
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zarkam21:
NelsonTA:
i think its 2(3y-x) ?
zarkam21:
@Vocaloid
NelsonTA:
oh im dumb nvm ignore me lol
zarkam21:
@Vocaloid
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Vocaloid:
Yeah good
zarkam21:
is that the final?
zarkam21:
zarkam21:
thanks
zarkam21:
the entry is still not valid
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zarkam21:
I do not think it would be =-4
zarkam21:
because wouldn't that fall in a different matrix
Goldenmattman2003:
Maybe theirs no solution.
zarkam21:
@Vocaloid
zarkam21:
This would be without the equal sign right
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zarkam21:
Ugh :(
Vocaloid:
I don't know what else it would be besides -4 or 4 sorry
zarkam21:
@Nnesha
zarkam21:
so should I just try -4
Nnesha:
how did u come up with that answer ? `2x+6y`?
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Nnesha:
a,b,c,d are the coefficients
zarkam21:
okay I used the numbers
zarkam21:
would it be 2 and 6
Nnesha:
i'm not sure how u got 2 and 6?
what's -2x+6y?
Nnesha:
you have to find the value of `a-b+c+d`
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Nnesha:
\[\left[\begin{matrix}\color{red}{a} &\color{green}{ c} \\ \color{blue}{b}& \color{orange}{d}\end{matrix}\right]\left(\begin{matrix}x \\ y\end{matrix}\right)=\left(\begin{matrix}C_1\\ C_2\end{matrix}\right)\]
a,b,c,d values \[\large\rm \color{ReD}{a}x+\color{blue}{b}y=C_1 \]\[\large\rm \color{green}{c}x+\color{orange}{d}y=C_2 \]
\[\large\rm find~~~\color{red}{a}-\color{blue}{b}+\color{green}{c}+\color{orange}{d}\]
zarkam21:
Well there is nothing more you can do with -2x+6y
Nnesha:
what's -2x+6y ? how did you get that?
zarkam21:
I did a-d which is 2-2
zarkam21:
excuse me -2-(2)
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zarkam21:
then I did plus 8
zarkam21:
actually I did 2-4
Nnesha:
it's `a-b`
zarkam21:
then plus 8
zarkam21:
yeah so 2-4
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Nnesha:
yes correct
zarkam21:
that's -2
zarkam21:
then I added the c value which is 8
zarkam21:
that is 6
zarkam21:
then didi 6-(-2)
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zarkam21:
8?
Nnesha:
8-2 =6 correct
and then we have to `add ` d
zarkam21:
d is -2?
Nnesha:
a-b+c `+d`
yes d is -2
zarkam21:
so 4?
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Nnesha:
yes
zarkam21:
thank you soo much
Nnesha:
np