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you are given an = 4n + 5 so for part i) you would just substitute n = 1 into the expression and find an then repeat this for n = 2, 3, 4
4(1)+5=9 4(2)+5=13 4(3)+5=17 4(4)+5=21
good. now, for part II it asks for the 1st term and the 10th term. let n = 1 and n = 10 and then calculate the an values just like you did for part I
so the first equation for 1 would be the same right?
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4(10)+5=45
yes, so 1st term = 9 and 10th term = 45
now for part III we use the sum formula
|dw:1510106097458:dw|
a1 = 9 an = 45 n = 10
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find sn
270
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