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Mathematics 20 Online
zarkam21:

Help please did i do this right???

zarkam21:

zarkam21:

Vocaloid:

the lines are right, just need to apply the shading

zarkam21:

I would basically color the whole graph right because everything is shaded

zarkam21:

or just the parts that meet

Vocaloid:

you would only graph the part that satisfies all three inequalities

Vocaloid:

there's a technique I use to make this a bit easier

Vocaloid:

|dw:1510375701081:dw|

Vocaloid:

instead of just shading everywhere, I draw lines parallel to the original line

Vocaloid:

|dw:1510375740609:dw|

Vocaloid:

and let's suppose I add another line, and this time I want to graph below it

Vocaloid:

|dw:1510375771859:dw|

Vocaloid:

you can see, visually, that the area that needs to be shaded is where both "types" or "directions" of lines overlap

Vocaloid:

|dw:1510375854523:dw|

Vocaloid:

it makes it a little easier to see which area satisfies all inequalities, especially when you have a lot of overlapping regions

Vocaloid:

but anyway, yeah, you would only shade in where all three inequalities are met

zarkam21:

would it be the little triangle at the top

zarkam21:

sorry for the late replies I am doing other work as well

Vocaloid:

be careful with the direction of the inequalities

Vocaloid:

for example, since we have y < -3x + 10 you would shade to the left of the dotted line

Vocaloid:

the direction to shade can be sometimes difficult to visualize especially for slanted lines

Vocaloid:

I'm trying to find something that can make it a bit easier to visualize |dw:1510376592157:dw|

zarkam21:

OH I know

zarkam21:

Its the triangle that is right by the zero

Vocaloid:

yeah , that's right ^^ just double checking something

Vocaloid:

|dw:1510376885182:dw|

Vocaloid:

|dw:1510376894459:dw|

Vocaloid:

^ that should be it

zarkam21:

Yup got it thank you !

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