Question

Will Upvote http://prntscr.com/hiw6jh

Answer 1

@Aeon

Answer 2

@JustSaiyan

Answer 3

Sorry, I am terrible at math. I can't help here. @Vocaloid @MARC

Answer 4

@Vocaloid

Answer 5

@MARC

Answer 6

@pooja195

Answer 7

@pooja195

Answer 8

Thanks JustSaiyan

Answer 9

I didn't do anything other than tag people who aren't online. :\

Answer 10

If no one helps in around..... 20 minutes, I will try to help, okay?

Answer 11

Thanks for introducing me to them. You helped XD

Answer 12

\(AE=CE\)

Answer 13

\(x^2-8=2x\)

Answer 14

solve for x using factorisation method

Answer 15

\(x^2-2x-8=0\)
\((x-4)(x+2)=0\)

Answer 16

x=4(acceptable bcoz it's positive),-2(not acceptable bcoz length can't hv negative value)

Answer 17

\(AC=AE+EC\)

Answer 18

\(AC=x^2-8+2x\)

Answer 19

\(Sub~x=4~into~the~eqn\)

Answer 20

\(AC=4^2-8+2(4)\)

Answer 21

\(AC=16-8+8\)

Answer 22

\(AC=?\)

Answer 23

Solve it @Comerpickles