Axis of symmetry got cut off
first draw a vertical line that divides the graph into two equal halves
the line would be in the middle right
good, now identify the x-value of that line
-2.5
actually 0
|dw:1512581077872:dw|
|dw:1512581086663:dw|
oh i accidently put the line on the 0 axis
from that it would be -1
good so the axis of symmetry is x = -1 to find the vertex we simply find the value of the graph at x = - 1
|dw:1512581205132:dw|
-3.5?
(-1,-3.5)
good, that's the vertex
to find the intercepts simply find the x-values where y = 0 and the y values where x= 0
***actually I believe the vertex is (-1,-4) the axis isn't drawn well
since it's 4 spaces below 0
so (0,0)(1,0)(2,0)(3,0)(-1,0)(-2,0)(-3,0)(-4,0)
how are you getting these numbers there are only two x-values where y = 0
|dw:1512581576538:dw|
ohhh where it intercepts duh
sorry
(1,0)(-3,0)
good, now what is the value of y when x = 0?
-2.5
(0,-2.5)
I think it's (0,-3) since each space is meant to represent 1 unit
So there would be three sets of intercepts (1,0)(-3,0)(0,-3)
yes
oh it isn't 2.5
I thought it was
yeah, each space is 1 unit and it's 3 units below y = 0
Intercepts : (1,0)(-3,0)(0,-3) Vertex: (-1,-4) Axis of symmetry : x=-1
well done
I need to go to a meeting, be back in a few hours
Sounds good =)
Join our real-time social learning platform and learn together with your friends!