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@563blackghost
@563blackghost
What did you find the points as?
\[\large Average~rate~of~change=\frac{f(a)-f(b)}{a-b}\]
(0, 80)
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where `a` ad `b` represents your point of time
(4, 405)
(0,80) (4,405) (8,2050.313)
ok
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like if you want to find average rate of change between 4 hours and 8 hours, \[\large AR1=\frac{80(1.5)^8-80(1.5)^4}{8-4}\]
81.25 from x = 0 to x = 4
ok and for 4 to 8?
411.32825 from x = 4 to x = 8
Now we would just divide the two from each other.
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5.0625 times as fast
Nice ;)
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