Prove: Every point on the perpendicular bisector of a segment is equidistant from the ends of the segment. https://wca.sooschools.com/media/g_geo_ccss_2016/9/q424a.gif https://wca.sooschools.com/media/g_geo_ccss_2016/9/q424b.gif AP = BP
Hello again :)
Hi!:)
Taking a look at your problem, just a moment :)
Okay no problem :) I know I dont have this completely correct, although this is what I have. I know its partially correct,just not sure what is wrong on it.. http://prntscr.com/hp4xbp
hmmm that's how i would solve it...
well maybe it's cause of how you inputted..try 0b instead of b0, since we go from first point to second.
It actually took my score down :x
O.O
Its gotta be the a0 thats wrong.. because when i moved the 0b around it made the question completely wrong...
hmmm
Ohh i see now
Try \(\bf{a^{2}+b^{2}}\) that should do it.
Pretty sure that is it, since we are trying to find distance.
oml. Thank yousooo much!
it worked?
Yes!! i dont know why I didn't think of that.. :') thank you!
awesome :) your welcome ^-^
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