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\[\ln(2x - 3) + \ln(x + 2) = 2\ln x\] Solve for x
@563blackghost
@Zepdrix
\(\implies \ln \left( (2x-3)(x+2) \right) = \ln x^2\) \(\implies (2x-3)(x+2) = x^2\) etc
Now I see what I was missing \[2x^2 - x - 6 = x^2\] \[x^2 + x - 6 = 0\] \[(x + 3)(x - 2)\] \[x = -3, 2\]
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