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PLS HELP!!! What is the solution of the system of equations? y = –2x + 8 y = x – 4
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@563blackghost
Well, a good first step is to set them equal to each other
Just another take: \(y = –2x + \color{red}{8} \qquad \square\) \(y = x – \color{red}{4} \qquad \triangle \) So i think that: \(\color{red}{8} = y + 2x \qquad \square'\) And: \( \color{red}{4} = - y + x \qquad \triangle' \) Or: \( \color{red}{8} = - 2y + 2x \qquad \triangle'' \) Consolidating this: 1) \(\color{red}{8} = y + 2x \qquad \square'\) 2) \( \color{red}{8} = - 2y + 2x \qquad \triangle'' \) And so \( \square' = \triangle'' \implies \text{???}\)
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