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Mathematics 29 Online
zarkam21:

Help with Physics/Math question

zarkam21:

@Vocaloid

zarkam21:

1 attachment
Vocaloid:

work done is equal to the change in kinetic energy so simply calculate the KE at 5 m/s and the KE at 9 m/s and then find the difference

zarkam21:

so 130*5 and 130*9

Vocaloid:

KE = (1/2)mv^2

zarkam21:

(1/2)130(5)^2 (1/2)130(9)^2

Vocaloid:

good, keep going

zarkam21:

3640

zarkam21:

SO A

Vocaloid:

good, well done

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