Question

Help please

Answer 1

intercepts are simple (simply break into its factors and set them equal to 0)

I actually don't remember how to find relative extrema (without using calculus) so I will be using software for this

Answer 2

Yeah that is fine

Answer 3

for example, for f(x) = (1/4)(x+2)(x-1)^2

we set

x + 2 = 0
and
x - 1 = 0

to find the x-intercepts

Answer 4

while you're solving for the x-intercepts...

the local max is (-1,1) and the local min is (1,0)

Answer 5

so for #20 is local max is (-1,1) and the local min is (1,0)

Answer 6

yes

Answer 7

have you figured out the x-intercepts yet?

Answer 8

yes

Answer 9

(-2,0)(1,0)

Answer 10

good

for y-intercepts we just let x = 0 and find f(x)

to save some time it's (0,1/2)

and that's it for 20

Answer 11

for 21 you need to factor the function first

do you know how to factor this?

Answer 12

yes one sec please

Answer 13

x(2x-5)(x+5)

Answer 14

good, now we set each factor to 0 to solve for the x intercepts

x = 0
(2x - 5) = 0
(x+5) = 0

Answer 15

x intercepts = (0,0)(5/2,0),(-5,0)
y intercept= (0,0)

Answer 16

good

the local max is (-3,66) and (1.37,-19.72) is the local min