?
start by factoring the numerator
um x-4
yup, so part I would be something like "x-4" can be cancelled out from the num and denominator
for part II just re-write G(x) after cancelling out (x-4)
g(x)=x^2-3
the original function is (x+1)(x-4)/(x-4) cancelling out the (x-4) gives us (x+1) as our new G(x)
so would it equal like would it be g(x)=x+1
yes part III is a removable discontinuity for part IV graph H(x) (it will look like x + 1 but it will have an open circle at x = -4)
okay so what is the equation maybe i can go on demos and see the entire graph
it's just (x+1) with an open circle at x = -4|dw:1515723194785:dw|
like that but with the right values
got it
*** should be an open circle at x = 4 not -4 anyway for the domain and range the missing point is (4,3) so x takes on all real values except 4 and y takes on all values except 3
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