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the coefficients of the dividend are just the coefficients of the numerator in order (since it's already in standard form and contains all relevant x terms)
so 16,80,1,5?
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the divisor is - 5 since (x+5) = 0 yields a vaule of x = -5
for part III carry out the synthetic division algorithm
Like this right>
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Yeah, the steps are there i will write those down
the directions say to use synthetic division
Isnt this it?
yes
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oky got that now for part IV
it would be 16 1 0?
the coefficients need to be applied to the actual polynomial so 16x^2 + x + 0
okay so the actual polynomial given in addition to 16x^2 + x + 0
or just 16x^2 + x + 0
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just the second one
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