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you will have three factors, each will look like (x-___) where the root goes into the blank
x-3
um x-3+i
x-3+i
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good just be careful with parentheses x-(3+i) and x - (3-i)
for part II) the two complex roots are x-(3+i) and x - (3-i) so multiply these together to get the quadratic (just be careful with parentheses/signs)
-2x-1xi-3+i
your final answer should not have i in it, check your calculations again (x-(3+i)) * (x-(3-i)) ^ use foil
x^2-6x+10
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good for part III the last factor is (x-3) so multiply that polynomial to get the answer for III
x^2+6x-3
(x-3)(x^2-6x+10) = ?
x^3-9x^2+28x-30
good, that's part III
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I'm gonna go hang out w/ some friends, idk if i'll be back later tonight
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