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@Vocaloid
kinematics eq 4
v^2=13+2(-2.1)
final velocity is already given (hint: the car is coming to a stop) you are solving for distance
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13=x+2(-2.1)
if the car is coming to a stop then what is the final velocity?
good, so set up the equation for delta x
0=13+2x
like that kind of?
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v^2 = v_o ^2 + 2a*delta x plug in everything except delta x and solve for delta x
0=13^2+2(-2.1)x
good, now solve for x
40.24
SO C
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