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Mathematics 7 Online
zarkam21:

a. What is the distance traveled by the car between 5 and 10 seconds? (2 points) b. What is the average speed of the car between 5 and 10 seconds? (Answer in km/s.) (2 points) c. Describe how the speed of the car changes throughout its test run. (2 points) d. If you had a graph of velocity versus time for this test, what would be the total area under the curve? (2 points)

zarkam21:

1 attachment
zarkam21:

a. 1km b. 2km c.It increases d. ?

Vocaloid:

a) distance at 10 seconds minus distance at 5 seconds = ?

Vocaloid:

|dw:1516898262366:dw|

Vocaloid:

|dw:1516898267468:dw|

Vocaloid:

0.03 - 0.01 = ?

zarkam21:

oh shoot i read it wrong it would be 0.02km

Vocaloid:

good b) is just that distance/2 seconds

zarkam21:

so 1

zarkam21:

0.02/2=0.01km

Vocaloid:

km/s but yes good

zarkam21:

The speed stays subtlety constant?

Vocaloid:

for c) well it starts with a velocity of approx 0.002 km/s during the first 10 seconds, accelerates to (0.02/5)km/s, then starts to level off at about 0.002 km/s again (feel free to check my calculations b/c i just kind of eyeballed it)

zarkam21:

and of course increases

Vocaloid:

I don't really know how qualitative/quantitative they want you to describe it

zarkam21:

Yeah i will take care of that, for the first then seconds would it be 0.002 or 0.003

zarkam21:

Just double checking

zarkam21:

first 10 seconds*

Vocaloid:

yeah next 15 seconds (from 10 to 15) I got 0.03 km so 0.03/5 km/s

zarkam21:

Starts with a velocity of approx 0.00 km/s during the first 10 seconds, accelerates to (0.03/5)km/s, then starts to level off at about 0.003 km/s again.

zarkam21:

Starts with a velocity of approx 0.003km/s during the first 10 seconds, accelerates to (0.03/5)km/s, then starts to level off at about 0.003 km/s again.

zarkam21:

I'm going to reword it just making sure the numbers are correct

Vocaloid:

yeah that's pretty much it for d) the area under the velocity curve is just the total distance 0.09 km

zarkam21:

Perfect. Thanks !!!

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