Mathematics
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zarkam21:
?
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zarkam21:
Vocaloid:
range for this log is all real vallues (no restrictions on y)
if log can only take a positive input what does that tell you about x?
zarkam21:
D?
Vocaloid:
x - 2 > 0
x > 2
zarkam21:
A
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Vocaloid:
good
zarkam21:
Vocaloid:
afaik the inverse graph is just reflected across the line y = x so
Vocaloid:
|dw:1517286183300:dw|
Vocaloid:
|dw:1517286188592:dw|
something like that
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zarkam21:
zarkam21:
zarkam21:
so B
Vocaloid:
yeah probably B
zarkam21:
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Vocaloid:
good that's what I got too
zarkam21:
zarkam21:
D?
Vocaloid:
200 = 40 * 1.02^x
divide both sides by 40
then take log base 1.02 on each side to eliminate that 1.02
zarkam21:
x=50.5
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Vocaloid:
keep everything in log form w/o simplifying since the answers are in log form
Vocaloid:
200 = 40 * 1.02^x
5 = 1.02^x
log_1.02(5) = x
zarkam21:
so that would be log1=(0.1)
Vocaloid:
where are you getting log1 and 0.1
zarkam21:
log_1.02(5) = x
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zarkam21:
don't i have to solve this
zarkam21:
oh nvm that is the simplified version right
Vocaloid:
|dw:1517287492279:dw|
change of base lets us replace the logs with lns
zarkam21:
so C
Vocaloid:
yes