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the desired population is 100 100 = 50(1.03)^x solve for x
oh wouldn't i just use the choices given to substitute for x
you could but that's kind of time-consuming and kind of defeats the point of learning to solve exponential equations
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good, so we round that down to 23 and say the year is 2023 (D)
you're close but the exponents in the denominator aren't negative
Oh B
gud
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D
for continuous interest you typically use A = Pe^(rt)
BB
good, b
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