math help plz.....
@moreso
@zarkam21 @Zepdrix
Can you show any work you did?
i didnt understand it
i havent done anything :/
The costs of the plans will have the form: $$ \large \rm base~ price + price ~per~ text \times \# texts$$ So for instance the first plan will be $$ \large 60 + 0.05 \times t $$
so that would be for 1, correct?
that is plan A for number 1. can you find plan B, C,
so it would be: 80+0.02*t
and C would be 99+0.05*t, right?
correct ;p
so... whats next?
plan D
and plan D is 75+0.007*t
yes, close. 75 + 0.07*t
how would i solve for 1?.... im so confused
that was number 1. you have 4 plans, and 4 algebraic expressions
oh, lol.
now, how would i do 2?
here we plug in 500 for t, in each other plans A,B,C,D
then we solve or no?
so id write that as an answer? or....
plan A
wait, what about the sales tax?
oh, ok
you will have to redo these 1. plan A : (60 + 0.05*t ) ( 1.06) plan B : (80 + 0.02*t) ( 1.06) plan C : (99+0.05*t) ( 1.06) plan D : (75 + 0.07*t) ( 1.06 ) 2. plan A : (60 + 0.05*500 ) (1.06 )= $90.10 plan B : (80 + 0.02*500) (1.06 )= $95.40 plan C : (99+0.05*500) ( 1.06 ) = $116.60 plan D : (75 + 0.07*500) ( 1.06 ) = $131.44
multiplying by 1.06 accounts for the tax
so the answer for 2 would still have been A
yes
h0w would i do 3?
@umm
@Tr3
@dude @Shadow
\(\color{#0cbb34}{\text{Originally Posted by}}\) @moreso you will have to redo these 1. plan A : (60 + 0.05*t ) ( 1.06) plan B : (80 + 0.02*t) ( 1.06) plan C : (99+0.05*t) ( 1.06) plan D : (75 + 0.07*t) ( 1.06 ) 2. plan A : (60 + 0.05*500 ) (1.06 )= $90.10 plan B : (80 + 0.02*500) (1.06 )= $95.40 plan C : (99+0.05*500) ( 1.06 ) = $116.60 plan D : (75 + 0.07*500) ( 1.06 ) = $131.44 \(\color{#0cbb34}{\text{End of Quote}}\) Now we need to recalculate for part 3, since you used 5GB of data, do you have an idea on how to reorganize this?
no
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